Question 72650
x(2x + 7) = -5
first distribute the x, put in standard form by move the 5 over to the right side and make the equation = 0;
{{{2x^2 + 7x +5=0}}}
Factor;
(2x + 5)(x+1)=0
make each =0
2x+5 = 0
2x = -5
{{{x = -5/2}}}
x+1=0
x=-1
so x = -1 or {{{x = -5/2}}}
:)