Question 861827
If one end of a line whose length is 13 Units is the point (4, 8)
and the ordinate of the other end is 3. What is its abscissa?
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Make (4,8) the center of a circle of radius 13
--> {{{(x-4)^2 + (y-8)^2 = 169}}}
Find the intersection(s) of x=3 and the circle.
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{{{(x-4)^2 + (y-8)^2 = 169}}}
{{{(3-4)^2 + (y-8)^2 = 169}}}
{{{y^2 - 16y + 65 = 169}}}
{{{y^2 - 16y - 104 = 0}}}
*[invoke solve_quadratic_equation 1,-16,-104]
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{{{y = 8 +- 2sqrt(42)}}}