Question 861913
{{{xy=-12}}} and assuming {{{y>x}}}, {{{y+x=1}}}.
Two equations and two unknown variables.


{{{y=1-x}}} from the second equation.
{{{x(1-x)=-12}}} substituted into the first equation.
{{{-x^2+x+12=0}}}
{{{x^2-x-12=0}}}
{{{highlight_green(highlight((x+3)(x-4)=0))}}}
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and you see what to do from that?