Question 861906
{{{2x + 5 < 8x + 3}}}


Do just as you would for an equality.
{{{2x+5-2x<8x+3-2x}}}
{{{2x-2x+5<8x-2x+3}}}
{{{5<8x+3}}}
{{{5-3<8x+3-3}}}
{{{2<8x}}}
{{{1/4<x}}}


You only need to watch for any step which multiplies or divides by a negative number, meaning, a negative VALUE.  Those steps require switching the order of the inequality symbol.  That kind of operation did not occur in this example.