Question 861846
Find sin2&#952; if sec&#952;=-4/3 and 90° <&#952;<180°
sec&#952;=1/cos&#952;=-4/3
cos&#952;=-3/4
sin&#952;=&#8730;(1-cos^2&#952;)=&#8730;(1-(9/16))=&#8730;(7/16)=&#8730;7/4
sin2&#952;=2sin&#952;cos&#952;=2*&#8730;7/4*-3/4=-6&#8730;7/16