Question 861881
4x^2-y^2-24x-4y+16=0 
{{{4(x-3)^2-(y+2)^2= -16 + 36 - 4}}}   Completing the Square
{{{4(x-3)^2-(y+2)^2=16}}}
{{{(x-3)^2/4-(y+2)^2/16=1}}}