Question 861826
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Hi
The point (x, y) is on the x-axis: P(x,0)
6 units from (1,4)
(1,4)
(x,0)  6 = {{{sqrt((1-x)^2 + 16)}}}
         (1-x)^2 + 16 = 36
            (1-x)^2  = 20
             1 - x = ± &#8730;20
             1 ± 4&#8730;5 = x