<PRE><B>Question 861798</B>
x=10a+b,
x/b=3,
y=10b+a,
y-x=36
a = 1,   b = 5,   
x = 15,   y = 51
check
15/5=3
51-15=36
ok


Just for fun how could you solve this by using logic and not algebra?
We are looking for a 2 digit product of 3 and a single digit from 0 to 9.
The factor is also the second digit
3*0=0
3*1=3
3*2=6
3*3=9
Now we have reached two digit products.
3*4=12
3*5=15
3*6=18
3*7=21
3*8=24
3*9=27

Only 3*5=15 satisfies the conditions
15 reversed =51
51-15=36
Success!</PRE>