Question 861729
That would be in a standard form, {{{y=a(x-h)^2+k}}, where {{{a>0}}}, and {{{h=k=0}}}, and therefore the form is much simpler, like {{{y=ax^2}}}.  Having a given point on the parabola allows you to find the value for a.  Solve the equation symbolically for a.


{{{a=y/x^2}}} and you have a point for x and y.
{{{a=5/(2^2)}}}


RESULT:  {{{highlight(y=(5/4)x^2)}}}