Question 861656

The length of rectangle is 5 more than the width. If the area is 20 square units. What are the dimension of the rectangle?
<pre>
Let width be W
Then length = W + 5
Therefore, W(W + 5) = 20
{{{W^2 + 5W = 20}}}
{{{W^2 + 5W - 20 = 0}}}
Use the quadratic equation formula to solve for W, or the width
Add 5 to that value to determine the value of the length
Then do a check!! 

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