Question 861435
{{{f(x)=a(x+2)(x-1)(x-4)}}}
{{{f(z)=a(z+2)(z-1)(z-4)}}}
{{{a=f(z)/((z+2)(z-1)(z-4))}}}
{{{f(x)=f(z)*((x+2)/(z+2))*((x-1)/(z-1))*((x-4)/(z-4))}}}