Question 72617
You are given that:
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g(x) = 70
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Then to find g(-10), all you need to do is to go to the equation for g(x) and substitute -10
for every x you find and simplify the result.
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In this problem you would get:
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g(-10) = 70
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Because there are no terms on the right side that contain an "x" there is no place that you
put a -10 on the right side. The right side just remains "70" and there is no need for 
further simplifying. So the answer to your question is just:
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g(-10) = 70 
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If your original problem had really been:
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{{{g(x) = x^2 - 4x + 2}}}
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and you were then asked to find g(-10) you would go about it in the same way. That is
you would go to g(x) and replace every x with -10 to get:
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{{{g(-10) = (-10)^2 - 4*(-10) + 2}}}
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Then you would simplify the right side knowing that {{{(-10)^2 = 100}}} and {{{-4*(-10) = 40}}}.
Substituting these values you would get:
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{{{g(-10) = 100 + 40 + 2 = 142}}}
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So for the new problem g(-10) would be 142.
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Hope this helps you to understand this type of operation a little better.