Question 72487
{{{(x-1)^2 + (y-8)^2 = 16}}}
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Here's a point to the right direction.  Look in your textbook for the standard form of the
equation of a circle.
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The above problem is a circle whose center is found by getting its x and y values through solving
the two equations x-1 = 0 and y - 8 = 0.
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The radius of the circle is the square root of the right side.
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In summary, the graph of this equation is a circle whose center is located located at (1,8) and
whose radius is 4.
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Hope this points you in a little better direction.  If you study how the equation for 
a circle is derived you will get a little better idea of how the above form comes about.
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And don't feel too badly about this.  The only reason I saw the answer immediately
was because the equation was written in a form that I recognized from a long time ago.