Question 72595
Given:
.
{{{f(x)=7x - 40}}}
.
and
.
{{{h(x)= -x^2 + 6x}}}
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f(5) means to go to the equation for f(x) and replace all the x's with 5.  When you do, then
you get:
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{{{f(5) = 7*5 - 40 = 35 - 40 = -5}}}
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Similarly, h(5) means to go to the equation for h(x) and replace all the x's by 5. And when you,
make this substitution you get:
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{{{h(5) = -(5^2) + 6*5 = -25 + 30 = +5}}}
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so adding f(5) to h(5) is equal to {{{-5 + 5}}} and the result is zero.
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So the answer to your problem is zero.
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Hope this helps you to understand how to deal with f(x), g(x), and h(x) when numbers are
given such as f(5), g(-2), and h(0).  Just plug those numbers in for x in the equations 
for f(x), g(x), and h(x).