Question 861216
If I have sec beta - cos beta = sin beta * tan beta how do I verify it?
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use x for beta
{{{sec(x)-cos(x)=sin(x)*tan(x)}}}
start with left side:
{{{sec(x)-cos(x)}}}
{{{1/cos(x)-cos(x)}}}
{{{(1-cos^2(x))/cos(x)}}}
{{{(sin^2(x))/cos(x)}}}
{{{sin(x)*(sin(x)/cos(x))=sin(x)*tan(x)}}}
verified: left side=right side
note: let me know if my solution is correct, helpful and understandable