Question 860866
let the integers be x,x+1 & x+2

x^2= (x+2)+10

x^2=x+12

x^2-x-12=0

x^2-4x+3x-12=0

x(x-4)+3(x-4)=0

(x-4)(x+3)=0

x=4 OR -3

positive integer = 4

4,5,6