<PRE><B>Question 860856</B>
In a study of men at a college (ages 20-29), the mean height was 70.9 inches whith a standard deviation of 3.5 inches. 
What height represents the 90th percentile?
Find the z-value with a left tail of 90%:: invNorm(0.9) = 1.2816
Find the corresponding height: h = z*s+u = 1.2816*3.5+70.9 = 75.39 inches
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What height represents the third quartile?
Find the z-value with a left tail of 75%:: invNorm(0.75) = 0.6745
h = 0.6745*3.5+70.9 = 73.26 inches
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Cheers,
Stan H.
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