Question 860660
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Hi,
n=50, p=0.25, x=25
{{{P (x)= highlight_green(nCx)(p^x)(q)^(n-x) }}} 
P(25) = {{{highlight_green(50C25)(.25^25)(.75)^(25) }}}
126410606437752
P(25) = {{{highlight_green(126410606437752)(.25^25)(.75)^25 }}} = .0000845
Note: We can use the normal distribution as a close approximation to the
 binomial distribution whenever n*p &#8805; 5 and nq &#8805; 5.
.25*50 = 12.5  and .75*50 = 37.5
Yes, We can use the normal distribution as a close approximation to the
 binomial distribution