Question 72541
Ok, your first steps are good. Now you have three equations in three unknowns, x, y, and z.
1) x+y+z = 98
2) x+y = 2+z
3) y = 4+x

Substitute equation 3) into equation 2) and solve for z.
2a) x+(4+x) = 2+z  Simplify and solve this for z.
2a) 2x+4 = 2+z
2a) z = 2x+2

Now substitute equation 3) (y = 4+x) and equation 2a) (z = 2x+2) into equation 1) and solve for x.
1a) x+(4+x)+2x+2) = 98  Simplify and solve for x.
1a) 4x+6 = 98
1a) 4x = 92
1a) x = 23 This is the first number.
3) y = 4+x
3) y = 4+23
3) y = 27  This is the second number.
2a) z = 2x+2
2a) z = 2(23)+2
2a) z = 46+2
2a) z = 48  This is the third number.