Question 860567
Here speeds are different and time too

but distance traveled by both is same

let jeff take t hours to reach the point of catchup

his distance is 5t

His wife leaves 1/2 hour later. so she takes (t-1/2) hour

d= 8 * (t-1/2)

8(t-1/2) = 5t

8(2t-1)/2=5t

4(2t-1)=5t

10t-4=5t

10t-5t=4

5t=4

t=4/5 hours

4/5 * 5 = 4 miles

Joan rate =8 mph
d=4

Joan time = 1/2 hour

she will catch up at 8.00 am