Question 860578
More data points would be better for seeing how good a linear fit they would be.


{{{m=(76-32)/(25)=44/25}}}, not reducible.
Using y=mx+b, solve to find b=y-mx; choose any desired point, best if either of those used in the slope computation.
{{{b=76-(44/25)25=76-44=32}}}
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Equation is {{{highlight(y=(44/25)x+32)}}}.