Question 860504
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Hi,
Question States***height of a triangle is 4 feet <u>less</u> than the base
1/2(x(x-4)=198
1/2(x^2-4x)=198
x^2-4x-396 = 0    |Hint: sqrt(396) = ~19.9  (2*8) ends in 6
(x -22)(x+18) = 0   (Tossing out the negative solution for unit measure)
   x = 22ft, the width.  Then length is 18ft
Or quadratic Eq always works
 *[invoke quadratic "x", 1, -4, -396]