Question 860432
Given sin(alpha)=8/9 and alpha is in quadrant I, find the exact value of 
sin(alpha/2) = sqrt[(1-cos(a))/2]. 
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If sin(a) = 8/9, cos(a) = sqrt[81-64]/9 = sqrt(17)/9
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Ans: sin(a/2) = sqrt[1-[sqrt(17)/9]/2]
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Cheers,
Stan H.
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