Question 860404
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Hi,
{{{(y-1)^2/highlight_green(3^2) - (x-2)^2/16 = 1}}} C(2,1) opening Up and down along x = 2
Vertices: V(2,-2) and V(2,4) {{{highlight_green(3)}}} units up and down from center
foci: F(2,-4) and F(2, 6)  |{{{sqrt(9+16)}}}| = 5 units up and down from center 
Standard Form of an Equation of an Hyperbola opening up and down is:
  {{{(y-k)^2/b^2 - (x-h)^2/a^2 = 1}}} with C(h,k) and vertices 'b' units up and down from center,  2b the length of the transverse axis
Foci {{{sqrt(a^2+b^2)}}}units units up and down from center, along x = h