Question 860374
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Hi,
CI	z -value
90%	z =1.645
92%	z = 1.751
95%	z = 1.96
98%	z = 2.326
99%	z = 2.576
mean of 2.45 and a standard deviation of 0.25
ME = 1.96(.25/(49)
CI: 2.45-ME < u <  2.45 + ME