Question 860090
2^y = 16^(x – 3) and 3^(y+2) = 27^x

2^(y) = 16^(x – 3)

{{{2^(y) = 2^(4(x-3))}}}

y=4(x-3)......................(1)

 {{{3^(y+2) = 27^x}}}

{{{3^(y+2)=3^3x}}}

y+2=3x
y-3x=-2......................(2)

substitute y
4(x-3)-3x=-2
4x-12-3x=-2
x=10
y=28