<PRE><B>Question 859858</B>
Find all angles theta such that 0 &lt; theta &lt; 2pi and theta satisfies the following: 
2sin^2(x)=1
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sin^2(x) = 1/2
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sin(x) = 1/sqrt(2) or sin(x) = -1/sqrt(2)
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x = pi/4 or (3/4)pi or (5/4)pi or (7/4)pi
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Cheers,
Stan H.
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