Question 859644
If three is added to twice the square of x, its 7x
{{{3+2x^2=7x}}}
Subtract 7x from both sides
{{{2x^2-7x+3=0}}}
Use the quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
Substitute a, b, c
{{{x=(7+-sqrt(7^2-4*2*3))/(2*2)}}}
Multiply
{{{x=(7+-sqrt(49-24))/4}}}
{{{x=(7+-sqrt(25))/4}}}
+-sqrt(25) is 5 or -5. First, we'll do +5
{{{x=(7+5)/4}}}
{{{x=12/4=3}}}
OR
{{{x=(7-5)/4}}}
{{{x=2/4=2}}}
X = 3 or 2