Question 859555
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Hi,
{{{log(7,(x+6)) - log(7,(x-3)) -log(7,(4)) = 0}}}
{{{log(7,( (x+6)/4(x-3) )) = 0}}}   |  Note: 7^0 = 1, yes setting to zero is HUGE
{{{(x+6)/4(x-3) = 1}}}
   x+6 = 4x-12
    18 = 3x
    x = 6