Question 859148
{{{M=6-2.5*log(I/I[o])}}}
{{{M-6=-2.5*log(I/I[o])}}}
{{{log(I/I[o])=(M-6)/(-2.5)}}}
{{{(I/I[o])=10^((M-6)/(-2.5))}}}
{{{I=I[o]*10^((M-6)/(-2.5))}}}