Question 859522
Complete the square.
{{{5x^2+4x-96=0}}}
{{{5(x^2+(4/5)x)=96}}}
{{{5(x^2+(4/5)x+4/25)=96+5(4/25)}}}
{{{5(x+2/5)^2=480/5+4/5}}}
{{{5(x+2/5)^2=484/5}}}
{{{(x+2/5)^2=484/25}}}
{{{x+2/5=0 +- 22/5}}}
{{{x=-2/5 +- 22/5}}}
{{{x=-24/5}}} and {{{x=4}}}
So then
{{{5x=-24}}}
{{{5x+24=0}}}
and
{{{x=4}}}
{{{x-4=0}}}
So,
{{{5x^2+4x-96=(5x+24)(x-4)}}}