Question 859363

You don't solve each triangle, you solve for the sides. Right?

Angle A = {{{90-54 = 36}}}°


Side b:
{{{tan(B)=b/a}}}
{{{tan(54)=b/9}}}
{{{b = 9*tan(54)}}}
{{{b=12.39}}}


side c:
{{{cos(B)=a/c}}}
We use the reciprocal trig function of cosine (secant) to make the computation of the fraction easier:
{{{sec(B)=c/a}}}
{{{sec(54)=c/9}}}
{{{c=9*sec(54)}}}
{{{c = 15.31}}}