Question 859129
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Hi, Previously Posted
p = .45,  n = 11
P(x = 1) = binompdf(11, .45, 1)= .0125
P(x &#8804; 4) =  binomcdf(11, .45, 4)= .3971
P(x &#8805; 8) = 1 – P(x &#8804; 7) = 1 - binomcdf(11, .45, 7)= .061