Question 859032
let the terms be a,ar,ar^2,ar^3

First condition
a+ar^2=40

a(1+r^2)=40

(1+r^2)=40/a

II condition

ar+ar^3=120

ar(1+r^2)=120

substitute (1+r^2)

ar(*(40/a) = 120

40r= 120
r=3

a(1+r^2)= 40
substitute r

a(1+9)=40

10a=40
a=4

CHECK

4, 12, 36,108,