Question 858971
 Given that 2^y = 16^(x – 3) and 3^(y+2) = 27^x, find the value of x + y


 2^y = 16^(x – 3) 

{{{2^y= 2^(4(x-3))}}}

y=4(x-3)

y=4x-12

4x-y=12..................(1)

and 3^(y+2) = 27^x, 

{{{3^(y+2)=3^(3x)}}}

y+2=3x

3x-y=2...................(2)

4	x		-1	y	=	12	.............1	
Total value								
3	x		-1	y	=	2	.............2	
Eliminate	y							
multiply (1)by		-1						
Multiply (2) by		1						
-4	x		1	y	=	-12		
3	x		-1	y	=	2		
Add the two equations								
-1	x				=	-10		
/	-1							
x	=	10						
plug value of			x	in (1)				
4	x		-1	y	=	12		
40			-1	y	=	12		
			-1	y	=	12		-40
			-1	y	=	-28		
				y	=	28		

x+y= 28+10=38


find the value of x + y