Question 858782
{{{x^2-5x-14 <0}}}
{{{(x+2)(x-7) <0}}}
When {{{x<-2}}}, left hand side is negative*negative=positive, so not less than zero
When {{{x>7}}}, left hand side is positive*positive=positive, so not less than zero
When {{{-2<x<7}}}, left hand side is positive*negative, so less than zero.
So {{{x^2-5x-14<0}}} when {{{-2<x<7}}}
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Verified by the graph
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{{{graph(300,300,-10,10,-10,10,x^2-5x-14)}}}