Question 858732
Original problem: solve using quadratic formula: {{{2x^2+4x+1=0}}}.

Using quadratic formula, I arrive at answer: {{{x=-1+or-(2sqrt(2))/4}}}. 
Using factoring I get: {{{x=-1+or-(sqrt(2))/2}}}. 
My book says answer: {{{x=(-2+or-sqrt(2))/2}}}? 
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*[invoke solve_quadratic_equation 2,4,1]
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All the answers are the same, just different forms.