Question 858645
The sum of three consecutive terms of an A.P. is 18 and their product is 162.Find the terms.

let the three terms be 
a-d, a , a+d

a-d+a+a+d =18

3a=18
a=6

(a-d)(a+d)(a) = 162

plug a =6

(6-d)(6+d)(6)=162



(36-d^2)*6 =162

36-d^2= 162/6

36-d^2= 27

d^2=9

d= +/-3

when d=3

3,6,9
when d=-3

9,6,3