Question 858263
A train 600 metre long passes a car running at 72 km/hr in same direction in which the train is going, in 10 seconds.
:
Change the speed of the car to meter/sec
{{{((72*1000))/3600}}} = 20 meters/sec
:
let s = speed of the train in meter/sec
write a distance equation, dist = speed * time 
10(s - 20 ) = 600
10s - 200 = 600
10s = 600 + 200
10s = 800
s = 800/10
s = 80 meters per sec
:
In km/hr: {{{(80*3600)/1000}}} = 288 km/hr
:
I know that is none of the answers, but that's what I get