Question 858299
let l be the length, r is radius of semi-circle, P is perimeter, A is area
A = (l * 2r) + 1/2 * pi * r^2
P = 2l + 2r + (1/2)pi2r
P = 2l + 2r + pi*r
6 = 2l + 2r + pi*r
2l = 6 - 2r - pi*r
l = 3 - r - (1/2)*pi*r
substitute for l in Area equation
A = [ (3 - r - (1/2)*pi*r)*2r] + 1/2 * pi * r^2
A = ( 6r - 2r^2 - pi*r^2) + (1/2 * pi * r^2)
A = 6r - 2r^2 - (1/2)*pi*r^2
A = r*(6 - 2r - (1/2)*pi*r)