Question 857445
{{{(sqrt(3x+1) +2)^2 = sqrt(5x+9)^2}}}


{{{3x+1+4*sqrt(3x+1)+4=5x+9}}}

After collecting like terms we get

{{{4*sqrt(3x+1)=2x+4}}}

or


{{{2*sqrt(3x+1)=x+2)}}}

squaring again leads to


{{{4(3x+1)=x^2+4x+4}}}

leading to

{{{x^2-8x=0}}}

solutions:  {0, 8}