Question 858245
If a,b,c are three consecutive integers, prove that 
log(1+ac)=2logb.
log(1+ac)=logb^2
b^2=1+ac
..
let a=1st consecutive integer=a
a+1=2nd consecutive integer=b
a+2=3rd consecutive integer=c
..
(a+1)^2=1+a(a+2)
a^2+2a+1=1+a^2+2a
verified: log(1+ac)=2logb