Question 858163
{{{(sqrt(2-x)) = x+4}}}

square both sides of the equation

(2-x) = (x+4)^2

2-x= x^2+8x+16

x^2+9x-14=0

x^2+9x =14

x^2+9x+(9/2)^2 =14 +(9/2)^2

(x+9/2)^2 = 14+(81/4)

(x+9/2)^2 = (56+81)/4


(x+9/2)^2 = (137)/4


take square root

x+9/2 = +/-sqrt(137)/2

x= -9/2 +/- sqrt(137)/2