Question 857726
 George and Bill left town A for town B at the same time.
 George was riding a bicycle at a constant speed, while Bill was driving a car.
 Bill traveled 5 times faster than George. Bill’s car broke halfway, and the rest of the way to the town B Bill traveled by foot with a speed equal to half of the George’s bicycle speed.
 Who got to B first: George or Bill
:
Let s = G's bilking speed
then
5s = B's driving speed
and
.5s = B's walking speed
;
Let d = the distance from A to B
:
Write a time equation; time = dist/speed
Find the difference in their travel time (t)
dif = B's drive time + B's walk time - G's bike time
t = {{{(.5d)/(5s)}}} + {{{(.5d)/(.5s)}}} - {{{d/s}}}
Use 5s as the common denominator
t = {{{(.5d)/(5s)}}} + {{{(5d)/(5s)}}} - {{{(5d)/(5s)}}}
t = {{{(5.5d)/(5s){{{ - {{{(5d)/(5s)}}}
t = {{{(.5d)/(5s)}}} is the time difference, if we got a neg value then B would be getting there first