<PRE><B>Question 858056</B>
If your notation means what it is as shown, then the first equation is {{{2*log(b,x)=y+3}}}, for the base b, used for both equations.  Treat the entire {{{log(b,x)}}} as one of the variables.


The system can be restated:
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{{{y-2log(b,x)=-3}}}
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{{{y-log(b,x)=1}}}
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Subtract one equation from the other equation to eliminate y, and solve first for {{{log(b,x)}}}; use this to solve for y.  You could then continue on to find what x is.</PRE>