Question 858007
2^-1a^-7b^4 as the denominator and 2ab^-3 as the numerator.


{{{2^-1a^-7b^4/2ab^-3}}} .


Look at the rules of exponents which you are learning; read them.

{{{(b^4)/(2^1*a^7*2a*(1/b^3))}}}

{{{(b^4)/(4a^8*(1/b^3))}}}, combines rules of exponents and commutative property of multiplication and simple multiplication fact

{{{((b^4)/(4a^8*(1/b^3)))(b^3/b^3)}}}, multiplying by 1 to simplify the complex fraction

{{{(b^4*b^3)/(4a^8*1)}}}
{{{highlight((b^7)/(4a^8))}}}