Question 857854
Find the equation in standard form of the parabola with vertex at (0,0) and focus (0,-3)
Given parabola opens down:
Its basic equation: 
x^2=-4py
axis of symmetry: x=0 or y-axis
p=3 (distance from focus to vertex on the axis of symmetry)
4p=12
Equation of given parabola:
x^2=-12y