Question 857919
Problem: 



given that p(x)=x^5-3x^3-x^2+1 what is p(2)



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Steps:



Replace EVERY copy of 'x' with 2 and evaluate. You use PEMDAS or the order of operations to evaluate.



{{{p(x)=x^5-3x^3-x^2+1}}}



{{{p(2)=(2)^5-3(2)^3-(2)^2+1}}} Replace EVERY copy of 'x' with 2



{{{p(2)=32-3(8)-4+1}}}



{{{p(2)=32-24-4+1}}}



{{{p(2)=8-4+1}}}



{{{p(2)=4+1}}}



{{{p(2)=5}}}



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Answer: {{{p(2)=highlight(5)}}}