Question 857730
1.{{{x = 5y + 8}}}
2.{{{4x + 2y = 10}}}
Use eq. 1 to substitute for x in eq. 2,
{{{4(5y+8)+2y=10}}}
{{{20y+32+2y=10}}}
{{{22y=-22}}}
{{{y=-1}}}
Then
{{{x=5(-1)+8}}}
{{{x=3}}}