<PRE><B>Question 857534</B>
On a recent trip, a trucker traveled 225 mi at a constant rate. Because of road conditions, the trucker then reduced the speed by 40 mph. An additional 35 mi was traveled at the reduced rate. The entire trip took 4 h. Find the rate of the trucker for the first 225 mi.
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let x=rate of the trucker for the first 225 mi
travel time=distance/rate
..
{{{225/x+35/40=4}}}
LCD:40x
40*225+35x=40x*4

9000+35x=160x
125x=9000
x=72
rate of the trucker for the first 225 mi=72 mph</PRE>